Question and Answer - Nuclear Physics #14

eyes.6 Page-21 M(A,Z) = 1/2 [fin)+yz+zz2] Y= -4aA -1 Zz ac A 1/3 + 49A A put value. M(A,Z) = 1/2/f(A) - 40AZ+acA 2M(A,R) =0 az Aconst. 1/6 Z+ 89AAFZZ=0 - 49A + (29CA -1/3 + 89AA1)2==0 40A Z= 2ac A 1/3 + 89A A 4 AA = 2(4 AV3 ac + 49A) A

29A = 49A A (I+ ac A1/3) 49A A/2 = as 1+1a 4aA ) A 2/3