Answer Key
University
Princeton UniversityCourse
PHY 103 | General Physics IPages
10
Academic year
2023
abdulsalam23745
Views
0
? T3 Find a, T, , T2 ,T3 T2 / T2 4Kg T, 3kg 2kg
ans: T3 a= 60-30 = $ 30/4 = 10/3 m/s 9 II T2 I 10/3=20-1, 2kg 10/3 2 4kg M 20/3 = 20-T, 20 I, roney 103mls 3kg 2ng T. = 20-20/3 = T1= 40/2 N 30N 60N T2:- t T2 10/3 10/3 = T2- = 30/3=3-30 31eg 3 30N T2 = LON = = =80N
? I, 10kg T2 5kg 15kg 120N Find acceleration and tension? ans: a= TDF a= 4m/s2 TM 5kg Ti; 4-T1/S a= 120 T, 30 SON T, = 20 = 12/3 =4m/s2 2 don't (ong) deredbecause Ir
T2 ; 4mls2 4 = T2-20 10 T, T2 10 40 = T2-20 - T2 = GON ? 10mg' Find accesati- on and reaction long ling 6kg ruth 4kg 3kg pull force? the 10m/s2 R1/4 = 10 ans: a= 130/3 4 R, = uon R1 a = 10m/s2 130-R2 3 = 10 R2 3kg 130N 130- R2 = 30 R2 = 130-30 = 100N
The A IUN B 4 kg C 2kg 1kg Find contact fore b/w A and B? 2m/52 a= 14/4 14-R = 2 ans: 4 41g R =2m/s 14-R = 8 INN
R= 14-8 = 6N ? Find acceleration R1 , Rn and R3? 30N 2kg 3kg 4kg 1kg R, R2 R3 ans: learning a= TDF Ri; TM 3=30-R1 30 a=30 I To a= 3m/s2 3=30-R, R1=30-3 R2; R1=27N 27 R2 2kg 21 R3 3kg 3 = 27-R2 2 3= 21-R3 - 6= 27-R2 3 R2=27-6 9=21-R3 = R2=21N R3=21-9 R3=12N
? a uniform rope of length I' is pulled by a force 'F' what is the tension in the ropie at a distance 'I'. From the end where it is applied repeame mass 'M'
ans= a-F M l m TE F L L length=m F a 1 M T F length =m m L F/m (mt) (m)l length= = mxl F.F-T L m m T= F- MF M = F- MilF M F=F-1/1F ? 5kg T=F (l-f) L 3kg 20N micdleesion Mrope = 2kg amo Dinoron Tat the mid of rope 2096 rope agoges any: a= 20 L 2kg 10 = 2m/s2 \ length = 2/1 1/20 = N/4 2 x 1/2 2 = I kg 2 21cg 2m/s2 2- 3kg T 1kg 3kg T 3 kg R/s = 2 T13 =2 T=ION K/4 = 2 T= 6rr T=8N 1/1
? 480-400 upon M, 20 A L 8 Find tension in the middle of roper M212 T mgsto YOON ans: m, = 20kg 4kg 2m/s2 12 120% M2 = 12kg - 40 120 160 Mrop = 8 kg 160N a= 480- - 400 T-160=2 2 40 = 30 2m/s2 T-160=32 40 T=32+160 T= 192N Tension a+'A'; T T-200 =2 20 8kg T 2m/s2 T- 200 =40 12kg T= 240ru 200N 1/4 of length; 1/4 18 = 2kg -440 = 2 14 12m/st Thkg T2 1-140=28 14x10 T2 =140+28
? what is the reaction force on the surfaces? 20, 20N 2kg N 4kg N2 mm surfacer ans: N, Go (40t20) ) GON m mommary 2kg a=0 norman o a=0 20N N,-20 Rest, uniform motion or I =0 N, - 20-0 EF =0 N, = 20N N, = ZON Rest in x axis N,=20 N2 EFx=0 n - 40-20=0 4kg Restiny axis = EFy=0 N2 = 60N YON ? 5kg 2kg 3kg 1n, any: 5kg a=0 Son a=TDF O= N,-50 TM N, = 5010 IN, a = TDF 2109 O= N1-01-20 TN, TOM = N2-50-20 20 = N2-70 0 - 13 - 100 = 143=100% = N2 = 70
Questions and Answers - Connected Bodies
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