Lecture Note
Equivalent Thermal Conductivity
-
University
Princeton University Course
PHY 103 | General Physics IPages
3
Academic year
2023
-
abdulsalam23745
Views
0
Equivalent thermal conductivity
, 44 1K2 A l l kepp= Rteff = Rt, Rb, REff = 21 Rt = l KellA KA Rt, l R,A Rt2= l KLA 21 =1 +1 keppA K,A K2A 2 Keff = 1 + 1 K1 1/4 K2 2 kelf = 122+14 K,K2 keff K,K2 I K1+K2 keff = 2kik2 kitk2 l K1 ? A A l K2 keff =?
KI angi A A l K2 I I I R \ Rt, Rt, 1 f 1 I 4 Keff 2A K,A K2A = K,A + K2A Keff 2A P kl = Keff 2A = Kit K2 K leff = K,t K2 2
Comments
Related Documents
- Questions and Answers - Density
- Elastomers
- Poisson's Ratio
- Strain
- Types of Stress
- Mechanical Properties of Solids
- Motion of Insect in a Rough Bowl
- Turning of Cycle on Frictionless Road
- Maximum Safe Speed on Taking Circular Turn
- Death Wall & Rotor
- Conical Pendulum
- Centripetal and Centrifugal Forces
- Constrained Motion
- Cutting of String
- Questions and Answers - Connected Bodies
- Questions and Answers - Spring Balance & Motion in a Lift
- Questions and Answers - Second Law of Motion
- Questions and Answers - Spring Balance
- Question and Answer - Impulse
- Characteristics of Sound
Equivalent Thermal Conductivity
Please or to post comments