Lecture Note
University
Massachusetts Institute of TechnologyCourse
Multivariable CalculusPages
1
Academic year
2022
Sporkz
Views
61
p {margin: 0; padding: 0;} .ft00{font-size:20px;font-family:Arial;color:#000000;} .ft01{font-size:18px;font-family:ArialMT;color:#000000;} .ft02{font-size:18px;line-height:22px;font-family:ArialMT;color:#000000;} Robot Arm Complete Then, you can do a similar analysis for y. And to save time, we've put this on the p set. Youfind that delta y is approximately equal to delta theta. This is the linear approximation step. Now that we are solving the problem, let us check our work. It is known that delta L minusdelta theta equals delta x and that delta theta equals delta y. We want the value of delta xto be 0 and the value of delta y to be 0.1. One reason we want this is because we want thetip of the finger to move from 2 comma one to 2 comma 1.1. The change in x, or delta x, is 0. And the change in y, or delta y, is 0.1. We put that in herebecause delta L minus delta theta is 0 and delta theta is 0.1. We want to find the values ofdelta L and delta theta. We can read off directly that delta L is 0.1 and delta theta is also 0.1. We solve for delta L,which we get as 0.1, and then we solve for delta theta, which also comes out to 0.1.
Robot Arm Analysis: Linear Approximation
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