Hwk Solutions: Operations with Integers

Hwk: Pg. 82: #9. 𝐴 = 2π𝑟ℎ r=4cm h=15 cm Substitute/Replace r by 4 and h by 15 in 𝐴 = 2π𝑟ℎ 𝐴 = 2π𝑟 ℎ = 2 π 4 ( ) 15 ( ) = 120 π The curved surface area of the cylinder with r=4cm and h=15 cm is 120π 𝑐𝑚 2 11. 𝐼𝑄 = 100𝑚 𝑝 a) m=16, p=14 𝐼𝑄 = 100 𝑚 𝑝 = 100 ×16 14 = 1600 14 = 800 7 = 114. 3 b)Similarly m=13, p=15 Mastery Test #1 will be on Monday Operations with integers (addition, subtraction, multiplication, division) Order of operations Substitution (Evaluating expressions)

Evaluate the following expressions and hand in your solutions a) 2 ( ) 5 ( ) 7 ( ) = − 10 ( ) − 7 ( ) = 70 b) −20 10 + 8 −2 = − 2 ( ) + − 4 ( ) =− 2 − 4 =− 6 c) − 1 − 5 + 9 − 2 + 3 =− 1 − 5 − 2 + 9 + 3 =−− 8 + 12 = 4 d) − 4 + 6 ( ) − 3 − 7 ( ) = 2 − − 4 ( ) = 2 + 4 = 6 e) − 8 ( ) + − 7 ( ) + + 14 ( ) − − 1 ( ) =− 8 − 7 + 14 + 1 =− 15 + 15 = 0