Lecture Note
University
Swansea UniversityCourse
EG-086 | Engineering SciencePages
4
Academic year
2023
Lloyd Reader
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0
(ii) Turbins (i) Assumptions: (a) PIE 00 (b) q = o (c) velocity = 0 [can be neglected hi = new bee 7.9 We = hi- h2 (iii) Compressor mag T + Same as turobine Wc = h,-h2 ( but S is negative) (iv) Heat exchange In heat exchanger is there there is work thensfer heat transfer but h, ta = h2 a = hth Love EN we Ask
Q. In oil cooler oil flows steading through a bundle of metal tubes. submerged in steady stream of cooling water at 90°C under study flow conditions the oil esters and leaves at 30°C while the water esters oil at @. 25°C leaves at 70°C The enthalpy -4 of and T is hist B8T + 10.5x10 T2 kJ/kg for what is temp the coding water flow oil. rate required cooling 2.78 igls of 2 38c oil goil 70°C 25c am water 2 1 n= 1.68T + 10.5 x104 T2 19g/kg C. moil= 2.78 kgls. Absested Energy in rejected , by bot fluid = enelgy by cold fluid (Q)oil = (Q) water Mail Coll (T101-T2011) = min CPW (T2w-TIW) mo = min mio (n1o- h2o) = min (hgw-haw) 1.68x 90 + LOTXIUM 90 = 159.705 51.345 kjlkg kJ/kg hio h2o = 1.68x30 10.5xt5 = hiw 1.68 = X 70+ 10.5 XLO 122.745 KJ/19g new = 1-68-25 +
15 2wstt Mw= moil (Mo-hzs) 2.78 (159.75-51-345) CPw (T2-TI) 4.178 (70-as) Mw= 1.6 1gts how h,w) " T1= if t1=t22 Mi=tfy 30.00 Programme) T2=H1 tzatts m2=ffs 9 at H7 SAVi SAMPLE AV: in " Ad. I it" Tame is Glod: ifs " 43c @ Q A Hurbo compressor delivers A 2.33 5/5 @ 0.276 Mfa which is heated at this pressure to 430°C freily expanded transfer in a turbine which delivers 1860 kwl during the expansion to the there is a heat calculate the of turbine exhaust temp. ) if the change b 0.09145/S sursounding K.E'sand P.E's are negligible. kg P1=0.276M S 2/4 Ti=43°C T2= 450°C Heat 31.0.276 MPa a to C V=2.33 2W= 1860kw T ~ 1c9"4 5 m3/5 (osls s Q:(0.09,MHI) a 2 steady flow equation Big Tax hz+q = b3tw 199, h2-h3 - W-q be- b3 = 1860- (10.09xw) by-h3=1950 KW
Now making Lills and value. ust R.H.S equal ai SCo moutiplying (iii) with L.H.S KW in ( b2-b3) 1950 [ Temp sbould is be ink is 0.276x10"x 2.33 in= Bvi = is 267x(243+43) RTI VJ m= 7.09 kgls Q-16 kg 2/3 7.09 (ths-b3)=1980 Q" Ga h2 7.09 DAY b2 (13/1g) 91604 2 24.25 = 275 INC kg I = 275 If S. mls 430-T3 - 275 1.015 and (p/s) Tg 1> 156.96 C kg m I bow kg. ICJ 5 BMS is
Turbins
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