Lecture Note
University
Princeton UniversityCourse
PHY 103 | General Physics IPages
2
Academic year
2023
abdulsalam23745
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Horizontal pipe (aeroplane pro- blems) P2 P1 V2 V, h h a, ca2 V, >V2 1/29V,4 n = 1/2 PV,+P P2)P, vertical pipe having uniform (ross secti- on
R V,DZA h, h,- h2 A K P2V2 h2 1/2 2 PV, + pgh,+ P, it Pgh, P 2 P2-P, = (h,-h2)Pg 1/2 PU,2 f soyh, - jogh, = 1/2 PV2 + P2-P1 = 1/28/2" pg(h,-h2) = t pg(h,-h2) = V1=V2
Horizontal Pipe and Vertical Pipe
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