Lecture Note
University
Princeton UniversityCourse
PHY 103 | General Physics IPages
3
Academic year
2023
abdulsalam23745
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Timeperiod of SHM T= 2TT we a= - -wex lal = w2x lal -w w= 1al x x
Translatory SHM 181 = KO F= -kx- 1 I F=ma F=ma F=m (-wrx) 2 T = Id T= 25 anguar clisp Eqn 1 and angular acceleration -KX = - mw'x T=219 0 K = w 101 m T= 211 us K m KO I T= 211 w T=299 I T= 211 K K m T= 211 m F=- Kx K ma = -KX a = ax at T= 211 m d'x +Kx =0 dt2 a 1al dx x at T= 211 x Differencial egn a = dv at 1al of SHM :- T=211 Displacement f end a T= 211 x Acceleration 211 x a Rotatory SHM Timeperiod F T= W K 211 K M C&O 2= 1 Energy OFSHM 2 I = IX KE = 1/2nv' I a = -KO V - -AW sin (wt (d) KE 8 = Anguar acceleration = I'm (-Awsin (06+0)) a = -KO I
RE 1ma'w'sin (wt + D) KE= 1-KA'sin (WHO) K mum
Time Period of SHM
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