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35 ares. The binding energy 17 CI nucleus is 298 Mev. Find its Atomic mass. MH = 1.007825 amu. Mn= 1.008665 ; 19m4xc2 = 931.5 MeV
501 35 f MA-A = -ve A " MAKA B= ZZHH + (A-z) mn - Ma] C2 amy T 298 MeV = [17x1.007825.+ 18 x1.008665- - Mes = 34.96908 amu < 35
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Question and Answer - Nuclear Physics #6