Question and Answer - Nuclear Physics #3

are 2.11 10 P P H' nucleus page-45 RH = 1.2 X (1) 1/3 = 1.2 fm Diameter = 2.4 f-m te J 2.4 fm E = p2c2+ mcc+ = (hc)2 Mect (1239)2 = +(0.511)2 12 (2.4)2 = 516.9069

K= 516.9069- 0.511 11. 515.739 MeV 0.515x109ev 11 (a)